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Shell element, laminate and orthotropic section

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Problem. In laminated and orthotropic shells the section stiffness matrices are given directly as input. In an isotropic shell these matrices are computed from the modulus of elasticity, Poisson's ratio and the thickness. The cases tested are an isotropic thick plate given through the laminate input, a specially orthotropic plate, a two-way CLT plate and an unsymmetric laminate. For the CLT plate the transverse shear force near the support is compared as well as the deflection.

Reference document. For the specially orthotropic plate the Navier series in Whitney's Structural Analysis of Laminated Anisotropic Plates is used. For the CLT plate the first-order shear deformation solution in Reddy's Mechanics of Laminated Composite Plates is used. The reference for the unsymmetric laminate is classical lamination theory.

The deflection of a specially orthotropic simply supported plate is computed with the Navier series.

w(x,y)=16 qπ6∑m∑nsin⁡mπ2 sin⁡nπ2m n[D11(ma)4+2(D12+2D66)(ma)2(nb)2+D22(nb)4]w(x,y) = \dfrac{16\,q}{\pi^6}\sum_m \sum_n \dfrac{\sin\frac{m\pi}{2}\,\sin\frac{n\pi}{2}}{m\,n\left[D_{11}\left(\frac{m}{a}\right)^4 + 2(D_{12}+2D_{66})\left(\frac{m}{a}\right)^2\left(\frac{n}{b}\right)^2 + D_{22}\left(\frac{n}{b}\right)^4\right]}

Classical lamination theory relates the section forces and moments to strain and curvature through this matrix. The matrix BB carries the coupling between membrane action and bending and is not zero for an unsymmetric lay-up.

[εκ]=[ABBTD]−1[NM]\begin{bmatrix}\varepsilon\\ \kappa\end{bmatrix} = \begin{bmatrix}A & B\\ B^{\mathsf T} & D\end{bmatrix}^{-1}\begin{bmatrix}N\\ M\end{bmatrix}

Numerical model. On all four edges of the plates the vertical translation and the rotation about the axis normal to the edge are held. In the unsymmetric laminate example the strip is supported at one end. The rotation is held at the support and the other end is left free.

Two-way CLT plate, L/t = 40

Parameters. a = 4 · t = 0.1 · mesh = 24×24 · Ds₁₁/Ds₂₂ = 1.635

Published source. The Navier series of first-order shear deformation theory for a specially orthotropic laminate

QuantityReferenceComputedDeviation
Centre deflection0.03605630.03602890.0759%

Note. The remaining deviation comes from the mesh density and shrinks as the mesh is refined.

Two-way CLT plate, transverse shear force at the middle of a supported edge

Parameters. a = 4 · mesh = 24×24 · x = 0.0833

Published source. The Navier series of first-order shear deformation theory (Mindlin)

QuantityReferenceComputedDeviation
Transverse shear force QxQ_x-17.2608-17.25140.0546%

Note. The transverse shear force is read at the middle of a supported edge, at the centre of the element next to the support (x=a/48x = a/48, y=a/2y = a/2). The reference value is computed at the same point. The shear force reaches its largest value at the middle of the supported edge, and this value is the direct input to the rolling shear check.

Two-way CLT plate, hand check of the layer stresses

Parameters. element count = 256 · q = 10

Closed form. Hand calculation with the transformed section

σ=E0 z MxxD11,τr=Qx SD11\sigma = \dfrac{E_0\,z\,M_{xx}}{D_{11}},\qquad \tau_r = \dfrac{Q_x\,S}{D_{11}}
QuantityReferenceComputedDeviation
Stress at the outer fibre, 0° layer11,442.811,442.80%
Rolling shear stress, 90° layer205.343205.3430%

Note. The moment and the shear force are read from the most heavily loaded elements of the model. The element next to the plate centre carries Mxx=15.23M_{xx} = 15.23 kNm/m and the element at the middle of a supported edge carries Qx=16.81Q_x = 16.81 kN/m. The lay-up gives the bending stiffness D11=765.4D_{11} = 765.4 kNm²/m, the outer fibre at z=0.05z = 0.05 m and, for the inner face of the upper cross layer, the weighted first moment S=E0t⋅0.04+E90t⋅0.02=9348S = E_0 t \cdot 0.04 + E_{90} t \cdot 0.02 = 9348. The stresses are in kPa. With Poisson's ratio zero, κx=Mxx/D11\kappa_x = M_{xx}/D_{11} is exact and the hand calculation reproduces the engine's result exactly.

Isotropic thick plate given through the laminate input

Parameters. t/a = 0.05 · ν = 0.2 · mesh = 24×24

Published source. The Navier series of first-order shear deformation theory (Mindlin)

QuantityReferenceComputedDeviation
Centre deflection0.000631050.0006306880.0574%

Note. The section matrices are built from an isotropic material and given directly as input. Before it is used, the reference series is checked in two cases. With a very large shear stiffness it returns to the Kirchhoff series, and for an isotropic thick plate it gives the Mindlin correction (1.01133).

Specially orthotropic simply supported plate

Parameters. a = 5 · t = 0.05 · E₁/E₂ = 30 · mesh = 16×16

Published source. Navier series, specially orthotropic plate (Whitney)

QuantityReferenceComputedDeviation
Centre deflection0.6351050.6350010.0164%

Note. Part of the remaining deviation comes from the mesh density and part from the reference solution leaving out shear deformation.

Unsymmetric laminate, axial tension

Parameters. t₁ = 0.06 · t₂ = 0.04 · E₁/E₂ = 3

Published source. In classical lamination theory the strain and curvature are computed with the inverse of the stiffness matrix.

[εκ]=[ABBD]−1[NM]\begin{bmatrix}\varepsilon\\ \kappa\end{bmatrix} = \begin{bmatrix}A & B\\ B & D\end{bmatrix}^{-1}\begin{bmatrix}N\\ M\end{bmatrix}
QuantityReferenceComputedDeviation
Vertical displacement at the free end-0.0618291-0.0618295< 0.001%

Note. The lower layer is thicker and stiffer, so the stiffness centre of the section lies e=10.9e = 10.9 mm below the mid-plane. The tension applied at the mid-plane is eccentric to this centre and puts a bending moment M=N e=10.9M = N\,e = 10.9 kNm/m on the strip. The strip therefore bends downward as it is pulled. The membrane-bending coupling is therefore measured by the vertical displacement. In a symmetric laminate this value is zero. A hand check with the beam analogy gives EIc=1412EI_c = 1412 kNm²/m about the stiffness centre and κ=M/EIc=7.73⋅10−3\kappa = M/EI_c = 7.73\cdot10^{-3} 1/m. At the tip of a cantilever held against rotation at the support the vertical displacement is w=κL2/2=0.0618w = \kappa L^2/2 = 0.0618 m. With Poisson's ratio taken as zero this result is the same as classical lamination theory.