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Semi-rigid connection

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Problem. A semi-rigid connection is a rotational spring between the element end and the node. A zero spring stiffness gives a release and an infinite one gives a rigid connection.

Reference document. The series spring relation is used, with the force method for the fixed-end forces. The case with two springs is cross-checked with an independent condensation.

In a semi-rigid connection the end moment is proportional to the relative rotation between the element end and the node.

M=S (θeleman−θdugum)M = S\,(\theta_{eleman} - \theta_{dugum})

The connection spring and the end stiffness of the element combine like two springs in series.

1ket=1S+L4EI\dfrac{1}{k_{et}} = \dfrac{1}{S} + \dfrac{L}{4EI}

Numerical model. The geometric stiffness and the mass matrix pass through the same link, so buckling and modal results are tested as well. In the twin-node model the translations, rxr_x and rzr_z are tied and only the in-plane rotation ryr_y is left independent.

End rotational stiffness, springs in series

Parameters. 4EI/L = 10,666.7 · L = 6

Closed form. Springs in series

1/keff=1/S+L/(4EI)1/k_{eff} = 1/S + L/(4EI)
QuantityReferenceComputedDeviation
Effective stiffness, S=104S = 10^45,161.295,161.290%

Note. The result is exact at all four spring stiffnesses between 10210^2 and 10810^8.

Uniformly distributed load, spring stiffness 10,000 at end i, end j rigid

Parameters. w = 12 · L = 6

Independent calculation. The force method, with the spring entering the flexibility diagonal as 1/S1/S

QuantityReferenceComputedDeviation
Fixed-end moment mim_i17.419417.41940%

Note. At the rigid end the moment is wL2/12=36.00wL^2/12 = 36.00.

Uniformly distributed load, spring stiffness 10,000 at both ends

Parameters. w = 12 · L = 6

Independent calculation. The force method, with the spring entering the flexibility diagonal as 1/S1/S

QuantityReferenceComputedDeviation
Fixed-end moment mim_i23.478323.47830%

Note. At the rigid end the moment is wL2/12=36.00wL^2/12 = 36.00.

Uniformly distributed load, spring stiffness 5,000 and 20,000 at the ends

Parameters. w = 12 · L = 6

Independent calculation. The force method, with the spring entering the flexibility diagonal as 1/S1/S

QuantityReferenceComputedDeviation
Fixed-end moment mim_i14.336314.33630%

Note. At the rigid end the moment is wL2/12=36.00wL^2/12 = 36.00.

One node, two different ends

Parameters. S = 8,000

Closed form. The definition itself, with the end rotation and the end moment obtained along two separate paths

QuantityReferenceComputedDeviation
Spring moment S(θel−θn)S(\theta_{el} - \theta_{n})21.428621.42860%

Note. The nodal rotation is -3.683036e-03 while the end rotation of the sprung member is -1.004464e-03. The rigid neighbour at the same node shares the nodal rotation exactly.

Portal frame, very stiff spring limit

Parameters. S = 1,000,000,000,000

Independent calculation. The rigidly connected frame obtained as the spring stiffness goes to infinity

QuantityReferenceComputedDeviation
Horizontal translation0.01119330.0111933< 0.001%

Note. A rigid connection gives 1.11933e-02 and a hinge 3.55681e-02, and the intermediate spring stiffnesses (10310^3, 10410^4, 10510^5) give 2.52880e-02, 1.41323e-02 and 1.15230e-02.

Pin-ended column, buckling

Parameters. mesh = 16 elements · L = 4

Published source. The critical load of a cantilever column

Pcr=π2EI/(2L)2P_{cr} = \pi^2 EI/(2L)^2
QuantityReferenceComputedDeviation
Critical load925.275925.276< 0.001%

Note. The convergence runs from 937.50 down to 925.28, from above and monotonically.

Beam with a hinge at mid-span, modal analysis

Parameters. mesh = 8 elements · L = 6

Independent calculation. An independent build, with twin nodes and an equality constraint on the translations

QuantityReferenceComputedDeviation
3rd vertical mode frequency288.857288.9740.0407%

Note. The first three vertical modes are 71.9495, 112.4513 and 288.9744 Hz with condensation and 71.949, 112.4344 and 288.8568 Hz with twin nodes. The difference comes from Guyan reduction.