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Result integration, frame element

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ExampleReferenceRecordsLargest deviation
Cantilever beam, tip load, on a plane cutClosed form60%
Simply supported beam, distributed loadClosed form20%

Problem. The section integration is tested on a cut through frame elements. On a cantilever the shear force and the moment are compared with the values that follow from statics.

Reference document. Static equilibrium is used.

On a cantilever the point load beyond the section produces this shear force and moment.

V=P,M=P (L−x)V = P,\qquad M = P\,(L-x)

Numerical model. The method is free body equilibrium. The end forces at the nodes on the cut are summed and reduced to a reference point.

Cantilever beam, tip load, on a plane cut

Closed form. Static equilibrium

V=P,M=P(L−x)V = P,\qquad M = P(L-x)
QuantityConditionReferenceComputedDeviation
Shear force VVx = 1.5 · L = 6 · P = -3030300%
Bending moment MMx = 1.5 · L = 6 · P = -301351350%
Shear force VVx = 3 · L = 6 · P = -3030300%
Bending moment MMx = 3 · L = 6 · P = -3090900%
Shear force VVx = 4.5 · L = 6 · P = -3030300%
Bending moment MMx = 4.5 · L = 6 · P = -3045450%

Simply supported beam, distributed load

Closed form. The moment relation for a simply supported beam

M(x)=wx(L−x)/2M(x) = wx(L-x)/2
QuantityConditionReferenceComputedDeviation
Bending moment at x=1.5x = 1.5x = 1.5 · L = 6 · w = -2067.567.50%
Bending moment at x=3.0x = 3.0x = 3 · L = 6 · w = -2090900%