Results.
| Example | Reference | Records | Largest deviation |
|---|---|---|---|
| Cantilever beam, tip load, on a plane cut | Closed form | 6 | 0% |
| Simply supported beam, distributed load | Closed form | 2 | 0% |
Problem. The section integration is tested on a cut through frame elements. On a cantilever the shear force and the moment are compared with the values that follow from statics.
Reference document. Static equilibrium is used.
On a cantilever the point load beyond the section produces this shear force and moment.
Numerical model. The method is free body equilibrium. The end forces at the nodes on the cut are summed and reduced to a reference point.
Cantilever beam, tip load, on a plane cut
Closed form. Static equilibrium
| Quantity | Condition | Reference | Computed | Deviation |
|---|---|---|---|---|
| Shear force | x = 1.5 · L = 6 · P = -30 | 30 | 30 | 0% |
| Bending moment | x = 1.5 · L = 6 · P = -30 | 135 | 135 | 0% |
| Shear force | x = 3 · L = 6 · P = -30 | 30 | 30 | 0% |
| Bending moment | x = 3 · L = 6 · P = -30 | 90 | 90 | 0% |
| Shear force | x = 4.5 · L = 6 · P = -30 | 30 | 30 | 0% |
| Bending moment | x = 4.5 · L = 6 · P = -30 | 45 | 45 | 0% |
Simply supported beam, distributed load
Closed form. The moment relation for a simply supported beam
| Quantity | Condition | Reference | Computed | Deviation |
|---|---|---|---|---|
| Bending moment at | x = 1.5 · L = 6 · w = -20 | 67.5 | 67.5 | 0% |
| Bending moment at | x = 3 · L = 6 · w = -20 | 90 | 90 | 0% |